5[2c+7]-3c=7[c+5]

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Solution for 5[2c+7]-3c=7[c+5] equation:


Simplifying
5[2c + 7] + -3c = 7[c + 5]

Reorder the terms:
5[7 + 2c] + -3c = 7[c + 5]
[7 * 5 + 2c * 5] + -3c = 7[c + 5]
[35 + 10c] + -3c = 7[c + 5]

Combine like terms: 10c + -3c = 7c
35 + 7c = 7[c + 5]

Reorder the terms:
35 + 7c = 7[5 + c]
35 + 7c = [5 * 7 + c * 7]
35 + 7c = [35 + 7c]

Add '-35' to each side of the equation.
35 + -35 + 7c = 35 + -35 + 7c

Combine like terms: 35 + -35 = 0
0 + 7c = 35 + -35 + 7c
7c = 35 + -35 + 7c

Combine like terms: 35 + -35 = 0
7c = 0 + 7c
7c = 7c

Add '-7c' to each side of the equation.
7c + -7c = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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